money-manager/util.py

44 lines
1.5 KiB
Python

from datetime import datetime, timedelta
def truncate_string(text: str, max_length: int) -> str:
if len(text) <= max_length:
return text
else:
return text[: max_length - 3] + "..."
# Not efficient at all, but I'm done trying to find efficient ways to do this
# Nothing on the internet when I try to search up "Python pay day on monday
# every two weeks" without it turning into something like today -> next
# monday + 14 days
# Either way, it's bounded by 52 weeks so it's actually probably going to be good enough
def next_payday(day=datetime.now()) -> datetime:
first_monday = datetime(day.year, 1, 1)
if first_monday.weekday() != 0:
days_until_next_monday = (7 - first_monday.weekday()) % 7
first_monday += timedelta(days=days_until_next_monday)
first_monday += timedelta(days=7)
next_payday = first_monday
# Calculate the next payday within a 14-day period
while next_payday <= day:
next_payday += timedelta(days=7)
if next_payday.weekday() != 0:
days_until_next_monday = (7 - next_payday.weekday()) % 7
next_payday += timedelta(days=days_until_next_monday - 1)
else:
next_payday += timedelta(days=7)
next_payday -= timedelta(days=1)
return next_payday
def rgb_tuple_to_hex(rgb_tuple):
# Ensure the values are within the valid range
color = [min(max(0, x), 1) for x in rgb_tuple]
color = [format(int(x * 255), "02x") for x in color]
rgb_hex = f"#{color[0]}{color[1]}{color[2]}"
return rgb_hex